`0.15g` of substance displaced `58.9cm^(3)` of air at `300K` and `746mm` pressure Calculate the molecular mass `("Aq Tension at" 300K = 26.7mm)` .

0.2 g of a substance displaced 65.2 mL of air at 300 K and 749 mm pressure. Calculate the molecular mass of the substance. (Aqueous Tension at 300 K is 26.7mm )

In a Victor Meyer's determination of molecular mass, 0.1015 g of an organic substance displaced 27.96 mL of air at 15°C and 766 mm pressure. Calculate the molecular mass of the substance (Aqueous tension at 15°C = 16 mm).

In a Victor Meyer's determination of molecular mass, 0.15 g of a volatile substance displaced 31.64 mL of air at 25°C and 755 mm pressure. Calculate the molecular mass of the substance.

0.1693 gm of a volatile substance when vapourised displaced 58.9 cm of air measured at 27^@C and 746 mm pressure. Calculate the molecular mass of the substance. (Aqueous tenstion at 27^@C=26.7mmHg .)

0.1693 gm of a volatile substance when vapourised displaced 58.9 mL of air measured at 27^@C and 746 mm pressure. Calculate the molecular mass of the substance. (Aqueous tenstion at 27^@C=26.7mmHg .)

In Victor Meyor's method, 0.2 g of a substance displaced 63 mL of air at 16^@C and 771 mm pressure. Calculated the molecular weight of the substance . At 16^@C aqueous tension = 13.5 mm.

7.00g of a gas occupies a volume of 4.1 litres at 300K and 1 atmosphere pressure. Calculate the molecular mass of the gas-

0.25g of an organic compound gave 30cm^(3) of moist dinitrogen at 288K and 745mm pressure. Calculate the percentage of nitrogen. (Aqueous tension at 288K = 12.7mm)