1 mole of hydrocarbon on complete combustion give 4 mole of `CO_(2)`. Calculate no of carbon in hydrocarbon.

0.2 gram -mole of an unsaturated hydrocarbon on complete combustion produces 26.4 g of CO_(2) . The molecular weight of the hydro-carbon is

10 ml of gaseous hydrocarbon on combustion gives 40 ml of CO_2_(g) and 50 ml of H_2O (vap) . The hydrocarbon is :

0.1 moles of Hydrocaron on complete combustion produced 17.6 gms of CO_(2) . How many Carbon atoms are present in each molecule of the hydrocarbon.

0.1 moles of Hydrocaron on complete combustion produced 17.6 gms of CO_(2) . How many Carbon atoms are present in each molecule of the hydrocarbon.

10 ml of hydrocarbon requries 55 ml of oxygen for complete combustion producing 40 ml of CO_(2) . The formula of the hydrocarbon is:

10 ml of hydrocarbon requries 55 ml of oxygen for complete combustion producing 40 ml of CO_(2) . The formula of the hydrocarbon is:

10mL of gaseous hydrocarbon on combustion gives 40ml of CO_(2)(g) and 50mL of H_(2)O (vapour) The hydrocarbon is .

10mL of gaseous hydrocarbon on combustion gives 40ml of CO_(2)(g) and 50mL of H_(2)O (vapour) The hydrocarbon is .

A gaseous hydrocarbon on complete combustion gives 3.38 g of CO_(2) and 0.690 g of H_(2)O and no other product. The empirical formula of the hydrocarbon is