`lim_(h->0)(e^(2x+2h) -e^(2x))/h=`

Instead of the usual definition of derivative Df(x), if we define a new kind of derivative D^*F(x) by the formula D*f(x)=lim_(h->0)(f^2(x+h)-f^2(x))/h ,w h e r ef^2(x) mean [f(x)]^2 and if f(x)=xlogx ,then D^*f(x)|_(x=e) has the value (A)e (B) 2e (c) 4e (d) none of these

Instead of the usual definition of derivative Df(x), if we define a new kind of derivative D^*F(x) by the formula D*f(x)=lim_(h->0)(f^2(x+h)-f^2(x))/h ,w h e r ef^2(x) mean [f(x)]^2 and if f(x)=xlogx ,then D^*f(x)|_(x=e) has the value (A)e (B) 2e (c) 4e (d) none of these

Instead of the usual definition of derivative Df(x), if we define a new kind of derivative D^*F(x) by the formula D*f(x)=lim_(h->0)(f^2(x+h)-f^2(x))/h ,w h e r ef^2(x) mean [f(x)]^2 and if f(x)=xlogx ,then D^*f(x)|_(x=e) has the value (A)e (B) 2e (c) 4e (d) none of these

Instead of the usual definition of derivative Df(x), if we define a new kind of derivative D^*F(x) by the formula D*f(x)=lim_(h->0)(f^2(x+h)-f^2(x))/h ,w h e r ef^2(x) mean [f(x)]^2 and if f(x)=xlogx ,then D^*f(x)|_(x=e) has the value (A)e (B) 2e (c) 4e (d) none of these

people living at Mars ,instead of the usual definition of derivative Df(x) define a new kind of derivative Df(x) by the formula Df(x)=lim_(h->0) (f^2(x+h)-f^2(x))/h where f^x means [f(x)]^2. If f(x)=xInx then Df(x)|_(x=e) has the value (a) e (b) 2e (c) 4e (d) non

If l_(1)=(d)/(dx)(e^(sinx)) l_(2)lim_(hto0) (e^(sin(x+h))-e^(sinx))/(h) l_(3)=inte^(sinx)cosxdx then which one of the following is correct?

lim_(hto0)(cos^(2)(x+h)-cos^(2)x)/(h) is equal to :

If f(x) =1/x , then show that lim_(hrarr0)(f(2+h)-f(2))/h=-1/4

lim_(x rarr0)(e^(2x)+e^(x)-2)/(x)