" salve the differential equation,"xdy-xdy=xydx

Solve the differential equation xdy+ydx=0.

The solution of the differential equation ydx-xdy=xydx is

Solve the differential equation : xdy/dx=y-x .

Solve the differential equation: ydx-xdy+(logx)dx=0

The curve,which satisfies the differential equation (xdy-ydx)/(xdy+ydx)=y^(2)sin(xy) and passes through (0,1), is given by

Solve the differential equation ylogydx-xdy=0

The solution of the differential equation xdy + ydx= xydx when y(1)=1 is

Solve the differential equation: (xdy - ydx) y sin (y/x) = (ydx + xdy) x cos(y/x)