`(dy)/(dx)= (x+y+1)/(x+y-1)` given `y=1` when `x=1`

Solution of the differential equation ((x+y-1)/(x+y-2))(dy)/(dx)=((x+y+1)/(x+y+1)), given that y = 1 when x = 1, is

Solution of the differential equation ((x+y-1)/(x+y-2))(dy)/(dx)=((x+y+1)/(x+y+1)), given that y = 1 when x = 1, is

Solve: log (dy)/(dx) = 4x - 2y-2 : given y = 1, when x = 1.

(dy)/(dx)=(y(2y-x))/(x(2y+x))=0 , given y=1, when x=1

Solve log(dy)/(dx)=4x-2y-2, given that y=1 when x=1

Solve: x(dy)/(dx)+2y=sqrt(1+x^(2)) , given y=1, when x=1

Solve: xy (dy)/(dx)=(x+2)(y+2) , given x= 1, when y =-1.

Solve log((dy)/(dx))=4x-2y-2 , given that y=1 when x=1.