The standard cell potential for the cell `Zn|Zn^(2+) (1 M)|| Cu^(2+) (1 M)| Cu`
given `E_(Cu^(2+)//Cu)^(@) = 0.34 V`
and `E_(Zn^(2+)//Zn)^(@) = - 0.76 V` is

The standard cell potential for the cell is , Zn|Zn^(2+)(1M)||Cu^(2+)(1M)|Cu [E^@ for Zn^(2+)//Zn=-0.76V, E^@ for Cu^(2+)//Cu=+0.34V]

Determine the maximum amount of work that can be derived from the cell, Zn|Zn^(2+)(1M)||Cu^(2+)(1M)|Cu. Given : E_(Zn^(2+)|Zn)^(@)=-0.76V and E_(Cu^(2+)|Cu)^(@)=+0.34V

What is the cell potential for following cell Zn(s)//Zn^(2+)(0.04M||Cu^(2+)(0.02M)//Cu(s) Given E_(Zn//Zn^(2+))^@ = -0.76V & E_(Cu//Cu^(2+))^@ = 0.34V

Calculate the e.m.f. of the cell Zn//Zn^(2+) (0.1M) "||" Cu^(2+) (0.01M) "|"Cu E_(Zn^(2+)//Zn)^(Theta)= -0.76 " V and "E_(Cu^(2+)//Cu)^(Theta)=0.34V

See whether the cell representation given below is in accordance with the conventation or not. If it is not, then write the correct representation and reaction of the cell. Calculate the standard EMF of the cell: Cu|Cu^(2+)||Zn|Zn^(2+) . ["Given : "E_(Cu^(2+)|Cu)^(@)=+0.34V, E_(Zn^(2+)|Zn)^(@)=-0.76V]

Calculate the maximum work that can be obtained from the daniell call given below, Zn(s)|Zn^(2+)(aq)||Cu^(2+)(aq)|Cu(s) . Given that E_(Zn^(2+)//Zn)^(@)=-0.76V and E_(Cu^(2+)//Cu)^(@)=+0.34V .

Calculate the maximum work that can be obtained from the daniell call given below, Zn(s)|Zn^(2+)(aq)||Cu^(2+)(aq)|Cu(s) . Given that E_(Zn^(2+)//Zn)^(@)=-0.76V and E_(Cu^(2+)//Cu)^(@)=+0.34V .