Show that the relation ‘is congruent to’ on the set of all triangles in a plane is an equivalence relation

Explanation

Now, `T`= set of all triangles

\begin{aligned}
&\mathrm{R}: \mathrm{T} \rightarrow \mathrm{T} \\
&\mathrm{R}=\left\{\left(\mathrm{T}_{1}, \mathrm{~T}_{2}\right): \mathrm{T}_{1} \cong \mathrm{T}_{2}\right\}
\end{aligned}



(i) For reflexive
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