(g)-1+sqrt(3)i

[3(cos40+i sin40)]*[4(cos80+i sin80)]=(A)-1+sqrt(3)i(B)4[-1+sqrt(3)i](C)2[-1+sqrt(3)i](D)6[-1+sqrt(3)i]

If i=sqrt(-)1, then 4+5(-(1)/(2)+(i sqrt(3))/(2))^(334)+3(-(1)/(2)+(i sqrt(3))/(2))^(365) is equal to (1)1-i sqrt(3)(2)-1+i sqrt(3)(3)i sqrt(3)(4)-i sqrt(3)

([(sqrt(2)+i sqrt(3))+(sqrt(2)-i sqrt(3))])/([(sqrt(3)+1sqrt(2))+(sqrt(3)-1sqrt(2))])

The value of ((1+sqrt(3)i)/(1 - sqrt(3)i))^(10) is

((-1+i sqrt(3))^(15))/((1-i)^(20))+((-1-i sqrt(3))^(15))/((1+i)^(20)) is

What is the value of ((-1+i sqrt(3))/(2))^(3n)+((-1-i sqrt(3))/(2))^(3n), where i=sqrt(-1)?

((-1+i sqrt(3))/(2))^(6)+((-1-i sqrt(3))/(2))^(6)+((-1+i sqrt(3))/(2))^(5)+((-1-i sqrt(3))/(2))^(6)