" If "cos alpha=(2cos beta-1)/(2-cos beta)th alpha tan(alpha)/(2)cot(beta)/(2)=

If cos alpha=(2cos beta-1)/(2-cos beta) then tan((alpha)/(2))*cot((beta)/(2)) has the equal to [where alpha,beta in(0,pi)]

If cos alpha=(2cos beta-1)/(2-cos beta) then tan (alpha/2) is equal to

cos2alpha=(3cos2beta-1)/(3-cos2beta) , then tan alpha=

If cos alpha=(2cos beta-1)/(2-cos beta),0

alpha and beta are acute angles and cos2 alpha=(3cos2 beta-1)/(3-cos2 beta) then tan alpha cot beta=

If alpha and beta are acute angles satisfying cos2 alpha=(3cos2 beta-1)/(3-cos2 beta), then tan alpha=sqrt(2)tan beta (b) (1)/(sqrt(2))tan beta(c)sqrt(2)cot beta(d)(1)/(sqrt(2))cot beta

cos 2 alpha =(3 cos 2 beta -1)/( 3-cos 2 beta), then tan alpha=

cos 2 alpha =(3 cos 2 beta -1)/( 3-cos 2 beta), then tan alpha=

alpha and beta are acute angles and cos2alpha = (3cos2beta-1)/(3-cos2beta) then tan alpha cot beta =