In a Wheatstone's network, `P=2Omega, Q=2Omega, R=2Omega and S=3Omega`. The resistance with which S is to be shunted in order that the bridge may be balanced is

In Wheatstone network, P=2Omega , Q=2 Omega , R=2Omega and S = 3 Omega . The resistance with which is to be shunted in order that the bridge may be balanced is:

In Wheatstone's network P = 2 Omega , Q = 2 Omega , R = 2 Omega and S = 3 Omega The resistance with which S is to shunted in order that the bridge may be balanced is

P, Q, R and S are four resistors of resistances 2, 2, 2 and 3 ohm respectively and are arranged to form a Wheatstone bridge network. Calculate the resistance with which the resistor S must be shunted in order that the bridge may be balanced.

In a Wheatstone bridge circuit, P=5 Omega, Q=6 Omega, R=10 Omega and S= 5 Omega . Find the additional resistance to be used in series with S, so that the bridge is balanced.

Four resistances arranged to form a Wheatstone's network are 8Omega, 12Omega, 6 Omega, and 27Omega . The resistance that should be connected across 27Omega resistance to balance the bridge is

For resistances arranged to form a wheatstone's network are 10 Omega, 15 Omega, 6 Omega and 36 Omega . What resistance should be connected across the 36 Omega resistance to balance the bridge ?

In the Wheatstone's bridge shown, P = 2 Omega, Q = 3 Omega, R = 6 Omega and S = 8 Omega . In order to obtain balance, shunt resistance across S must be