`|[3,-1,1],[8,1,-2],[5,-2,-3]|`

Delta=|[5,3,8],[2,0,1],[1,2,3]|=

If {[([3,1,2],[8,9,5],[1,1,3])([1,3,3],[3,2,7],[3,7,9])([3,8,1],[1,9,1],[2,5,3])])}^(2)=([a_(1),a_(2),a_(3)],[b_(1),b_(2),b_(3)],[c_(1),c_(2),c_(3)]) then the value of |a_(2)-b_(1)|+|a_(3)-c_(1)|+|b_(3)-c_(2)| is

If A=[[0, 1, 2], [1, 2, 3], [3, a, 1]] and A^(-1)=(-1)/(2)[[-1, 1, -1], [8, -6, -2k], [-5, 3, -1]] , then

If A=[[-5,-8,0],[3,5,0],[1,2,-1]], then A' is

If A=[[-5,-8,0],[3,5,0],[1,2,-1]], then transpose of A is

Without expanding prove that: |[12, 2, 4, -5, 1],[-8, 1, -5, 2, -1],[6, 4, a ,-3, 2],[-10, 2, 1 ,3 ,4],[-2, 4, 6 ,8, -5]|=|[12, -4, -8, 10, -2],[4, 1, -5, 2, -1],[-3, 4, a, -3, 2],[5, 2, 1, 3, 4],[1, 4, 6, 8, -5]| .

If A=[[-3,1,2],[0,0,1],[-3,5,0]] ,then 8|A|

If A=[(3,1),(-1,2)] then A^2= (A) [(8,-5),(-5,3)] (B) [(8,-5),(5,3)] (C) [(8,-5),(-5,-3)] (D) [(8,5),(-5,3)]

If A=[(3,1),(-1,2)] then A^2= (A) [(8,-5),(-5,3)] (B) [(8,-5),(5,3)] (C) [(8,-5),(-5,-3)] (D) [(8,5),(-5,3)]