A parallel plate capacitor is charged to a potential difference of 50V. It is discharged through a resistance. After 1 second, the potential difference between plates becomes 40V. Then

A parallel plate capacitor is charged to a potential difference of 50 volts. It is then discharged through a resistance for 2 seconds and its potential drops by 10 volts. Calculate the fraction of energy stored in the capacitance.

A parallel plate capacitor is charged to a potential difference of 50 volts. It is then discharged through a resistance for 2 seconds and its potential drops by 10 volts. Calculate the fraction of energy stored in the capacitance.

A capacitor is charged to a potential difference of 100V and then it is connected across a resistor.After one second,the potential drop across the plates of the capacitor becomes 80V .Then after 2 sec the potential difference

The plates of capacitor are charged to a potential difference of 100V and then connected across a resistor.When the potential difference between the plates of the capacitor is 60V ,what is the fraction of the stored energy which has been dissipated?

The plates of a parallel plate capacitor are charged to a potential difference of 117 V and then connected across a resistor. The potential difference across the capacitor decreases exponentially with to time.After 1s the potential difference between the plates is 39 V, then after 2s from the start, the potential difference (in V) between the plates is