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If f: R ->Ris defined by f(x) = x^2- 3x...

If `f: R ->R`is defined by `f(x) = x^2- 3x + 2`, find `f(f(x))`.

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Given:
`f(x) = x^2- 3x + 2`
`f(f(x))=f( x^2- 3x + 2)`
`f(x^2- 3x + 2)= (x^2- 3x + 2)^2-3 (x^2- 3x + 2)+2`
`=x^4+9x^2+4-6x^3-12x+4x^2-3x^2+9x-6+2`
`=x^4-6x^3+10x^2-3x`
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