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Let f,\ g and h be functions from R to R...

Let `f,\ g` and `h` be functions from `R` to `R` . Show that `(fg)oh=(foh)(goh)`

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Verified by Experts

To show:
` (f.g)oh=(foh).(goh)`
Let
`((f.g)oh)(x)`
`=(f.g)(h(x))`
`=f(h(x)).g(h(x))`
`=(foh)(x).(goh)(x)`
`=(foh).(goh)(x)`
...
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