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Let f: A->A be a function such that fof=...

Let `f: A->A` be a function such that `fof=f` . Show that `f` is onto if and only if `f` is one-one. Describe `f` in this case.

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Verified by Experts

Since A be a finite set and fof=f
So,
f:A→ A is onto that means every element in Y
set has a preimage in X set
That also means that every element in
X must have only one image in Y because both
X,Y are equal so the function is one - one
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