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Consider `f : N ->N`, `g : N ->N`and `h : N ->R`defined as`f (x) = 2x`, `g (y) = 3y + 4`and `h (z) = s in z`, `AA`x, y and z in N. Show that ho(gof ) = (hog) of.

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Given,
`LHS = ho(gof ) `
`=> ho(g(f(x)) `
`=> h(g(2x)) `
`=> h(3(2x) + 4) `
`=> h(6x +4) `
`=> sin(6x + 4)`
and,
...
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