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If `f: AvecBa n dg: BvecC` are one-one functions, show that `gof` is one-one function.

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Suppose `a1,a2∈A`
such that
`(gof)(a1)=(gof)(a2)` and
`=>g(f(a1))=g(f(a2))`
`=>g(f(a1))=g(f(a2)) `
...
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