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If f(x)=e^x and g(x)=(log)e x(x >0), fin...

If `f(x)=e^x` and `g(x)=(log)_e x(x >0),` find `foga n dgofdot` Is `fog=gof?`

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Given,
`f(x)=e^x;g(x)=lnx `
`fog(x)=e^(lnx)=x`
`gof(x)=ln(e^x)=x`
Hence, `fog(x)=gof(x)`
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