If `f:(-pi//2,pi//2)->R` and `g:[-1,\ 1]->R` be defined as `f(x)=tanx` and `g(x)=sqrt(1-x^2)` respectively. Describe `fog` and `gof` .

Explanation

Неге,` f(x)=tan x and g(x)=sqrt{1-x^{2}}`


Therefore` f o g=f(g(x))=f(sqrt{1-x^{2}})=tan (sqrt{1-x^{2}}) `
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Rightarrow g o f=g(f(x))=g(tan x)=sqrt{1-tan ^{2} x}`