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If the function `f: C->C` be defined by `f(x)=x^2-1` , find `f^(-1)(9)` and `f^(-1)(8)` .

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Verified by Experts

(i) for `f^(−1)(9)`
` x^2−5x+9=9`
` x(x−5)=0`
` x=0,5`
Hence `f^(−1)(9)=0,5`
(ii) for `f^(−1)(8)`
`X^2+5x+9=8`
` X^2+5x+1=0`
` ...
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