Show that `f: [-1, 1] ->R`, given by `f(x)=x/((x+2)`is one- one . Find the inverse of the function `f: [-1, 1]`

Explanation

`x_{1}, x_{2} in {D}_{{f}}`
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f(x_{1})=f(x_{2}) arrow frac{x_{1}}{x_{1}+2}=frac{x_{2}}{x_{2}+2} `
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Rightarrow x_{1}(x_{2}+2)=x_{2}(x_{1}+2) `
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Rightarrow x_{1} x_{2}+2 x_{1}=x_{1} x_{2}+2 x_{2} `
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Rightarrow x_{1}=x_{2}`


So f is one-one
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