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The value of parameter alpha, for which ...

The value of parameter `alpha`, for which the function `f(x) = 1+alpha x, alpha!=0` is the inverse of itself

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`f(x)=y,`S o `1+alpha x=y`
` Rightarrow {x}=frac{{y}-1}{alpha}`
` therefore f^{-1}(y)=frac{y-1}{alpha}`
` ...
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