If `f: Q->Q ,\ \ g: Q->Q` are two functions defined by `f(x)=2x` and `g(x)=x+2` , show that `f` and `g` are bijective maps. Verify that `(gof)^(-1)=f^(-1)\ og^(-1)` .

Explanation

To show that the functions \( f \) and \( g \) are bijective maps and verify that \( (g \circ f)^{-1} = f^{-1} \circ g^{-1} \), we will follow these steps:

### Step 1: Show that \( f \) is bijective

1. **Define the function**: The function \( f \) is defined as:
\[ f(x) = 2x \]
...