If `f: C->C` is defined by `f(x)=x^4` , write `f^(-1)(1)` .

Explanation

Let `f^{-1}(1)=x quad cdots(1)`



`Rightarrow {f}({x})=1 `


`Rightarrow {x}^{4}=1 quad text { [Since, } {f}({x})={x}^{4}] `


`Rightarrow {x}^{4}-1=0 `


`Rightarrow({x}^{2}-1)({x}^{2}+1)=0 ldots ldots ldots ldots ldots[{a}^{2}-{b}^{2}=({a}-{b})({a}+{b})] `


`Rightarrow({x}-1)({x}+1)({x}^{2}+1)=0 ldots ldots ldots ldots ldots[{a}^{2}-{b}^{2}=({a}-{b})({a}+{b})]`



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