If `f\ : R-: R` be defined by `f(x)=(3-x^3)^(1//3)\ ,` then find `fof(x)`

Explanation

Now,


`f circ f(x) =f[f(x)]=f[(3-x^{3})^{1 / 3}]`


`=[3-{(3-x^{3})^{1 / 3}}^{3}]^{1 / 3} `


`=[3-(3-x^{3})]^{1 / 3}=(x^{3})^{1 / 3} `


`=x`