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The function f: A->B defined by f(x)=-x^...

The function `f: A->B` defined by `f(x)=-x^2+6x-8` is a bijection, if `A=(-oo,\ 3]` and `B=(-oo,\ 1]` (b) `A=[-3,\ oo)` and `B=(-oo,\ 1]` (c) `A=(-oo,\ 3]` and `B=[1,\ oo)` (d) `A=[3,\ oo)` and `B=[1,\ oo)`

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Verified by Experts

`A=(-infty, 3]` and `B=(-infty, 1]`

`f(x)=-x^{2}+6 x-8`, is a polynomial function

And the domain of polynomial function is real number.

`therefore x in R`

`f(x)=-x^{2}+6 x-8 `

...
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