Let f be an injective map. with domain (x, y, z and range (1, 2, 3), such that exactly one following statements is correct and the remaining are false : `f(x)=1 , f(y) != 1, f(z) !=2` The value of `f^-1)(1)` is

Explanation

Case `-1: {Let} f(x)=1 {P}` be true.


Then, `f(y) neq 1` and `f(z) neq 2` are false.


So,f `(y)=1` and `f(z)=2`


`Rightarrow f(x)=1, f(y)=1`


`Rightarrow x` and `y` have the same images.


This contradicts the fact that `f` is one-one.


Case `-2:` Letf `(y) neq 1` be true.


Then, `f(x)=1` and `f(z) neq 2` are false.


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