Let `f: R-{n}->R` be a function defined by `f(x)=(x-m)/(x-n)` such that `m!=n` 1) f is one one into function2) f is one one onto function3) f is many one into funciton4) f is many one onto funcionn then

Explanation

Correct option is B)

one−one test:

Let `x_1`​ and `x_2`​ be two elements in the domain
`R−{n}` such that

`⇒ f(x_1​)=f(x_2​)`


`⇒ (x_1​−m)/(x_1​−m​)=(x_2​−m)/(x_2​−n)​`

`⇒ (x_1​−m)(x_2​−n)=(x_1​−n)(x_2​−m)`

`⇒ x_1​x_2​−nx_1​−mx_2​+mn=x_1​x_2​−mx_1​−nx_2​+mn`

...