Let `f(x)=x^2` and `g(x)=2^x` . Then the solution set of the equation `fog(x)=gof(x)` is `R` (b) {0} (c) {0, 2} (d) none of these

Explanation

Given `f(x)=x^2` and `g(x)=2^x
`

So,

`f(g(x))={g(x)}^2`


`f(g(x))={2^x}^2=2^(2x)`

And,

`g(f(x))=2^(f(x))`
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