If `g(f(x))=|sinx|a n df(g(x))=(sinsqrt(x))^2` , then `f(x)=sin^2x ,g(x)=sqrt(x)` `f(x)=sinx ,g(x)=|x|` `f(x=x^2,g(x)=sinsqrt(x)` `fa n dg` cannot be determined

Explanation

Given,

`g(f(x))=∣sinx∣=sqrt((sinx)^2)
`​

`f(g(x))=(sinsqrt(x))^2=sin^2sqrt(x)
`​


`∴f(x)=sin^2sqrt(x)` and `g(x)=sqrt(x)`
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