Let `g(x)=1+x-[x]a n df(x)={-1, x<0 0, x=0f, x >0` . Then for all `x ,f(g(x))` is equal to (where [.] represents the greatest integer function). `x` (b) `1` (c) `f(x)` (d) `g(x)`

Explanation

Correct option is B)

`(1)` When `x>(-1)`

then,

` g(x)=1+x−[x]`

`=1+x−(−1) `

`=2+x`

So,

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