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Let S={a+sqrt(2)\ b\ : a ,\ b in Z}dot ...

Let `S={a+sqrt(2)\ b\ : a ,\ b in Z}dot` Then, prove that an operation * on `S` defined by `(a_1+sqrt(2)b_1)*(a_2+sqrt(2)b_2)=(a_1+a_2)+sqrt(2)(b_1+b_2)` for all `a_1,\ a_2,\ b_1,\ b_2 in Z` is a binary operation on `Sdot`

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`(a_1+sqrt(2)b_1)*(a_2+sqrt(2)b_2)`
`=>(a_1+a_2)+sqrt2(b_1+b_2)`
here,`(a_1+a_2)inZ`
and also `sqrt2(b_1+b_2)inZ`
so,`(a_1+a_2)+sqrt2(b_1+b_2)in S`
Hence * is a binary operation.
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