If `x=cos e c[tan^(-1){"cos"(cot^(-1)(sec(sin^(-1)a)))}]` and `y="sec"[cot^(-1){"sin"(tan^(-1)(cos e c(cos^(-1)a)))}]`

Answer

`X=Y`

Explanation

`x=\csc (\tan ^{-1}(\cos (\cot ^{-1}(\sec (\frac{\sin ^{-1} a})))))`


`\sin \theta=a`


`x=\csc (\tan ^{-1}(\cos (\cot ^{-1}(\frac{1}{\sqrt{1-a^{2}}}))))`


`\cot \alpha=\frac{1}{\sqrt{1-a^{2}}}`


`x=\csc \frac{(\tan ^{-1}(\frac{1}{\sqrt{2-a^{2}}}))}{\beta}`


`\tan \beta=\frac{1}{\sqrt{2-a^{2}}}`


`x=\sqrt{3-a^{2}}`


`x^{2}+a^{2}=3`


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