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Solve: cos{2\ sin^(-1)(-x)}=0...

Solve: `cos{2\ sin^(-1)(-x)}=0`

Text Solution

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Let `\sin ^{-1}(-x)=y` where `y \in[\frac{-\pi}{2}, \frac{\pi}{2}]`
`\Rightarrow \sin y=-x`
According to question
`\Rightarrow \cos 2y=0 `
`\Rightarrow 1-2 \sin ^{2}y=0 `
...
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