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Solve: sin^(-1)x=pi/6+cos^(-1)x...

Solve: `sin^(-1)x=pi/6+cos^(-1)x`

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`sin ^{-1} x-cos ^{-1} x=pi / 6`

`implies sin ^{-1} x+cos ^{-1} x-2 cdot cos ^{-1} x=pi / 6`

`implies pi / 2-2 cdot cos ^{-1} {x}=pi / 6`

`implies-2 cdot cos ^{-1} {x}=pi / 6-pi / 2`

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