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solve:sin^-1x+sin^-1 2x=pi/3...

solve`:sin^-1x+sin^-1 2x=pi/3`

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The correct Answer is:
`x= frac{sqrt{3}}{2 sqrt{7}} `

ATQ, $$ \begin{aligned} &\sin ^{-1}(\mathrm{x})+\sin ^{-1}(2 \mathrm{x})=\pi / 3 \\ &\Rightarrow \sin ^{-1} x+\sin ^{-1}(2 x)=\sin ^{-1}\left(\frac{\sqrt{3}}{2}\right) \\ &\Rightarrow \sin ^{-1} x-\sin ^{-1}\left(\frac{\sqrt{3}}{2}\right)=-\sin ^{-1}(2 x) \\ &\Rightarrow \quad \sin ^{-1}\left(\frac{x}{2}-\frac{\sqrt{3}}{2} \sqrt{1-x^{2}}\right)=\sin ^{-1}(-2 x) \\ &\Rightarrow \quad\left(\frac{x}{2}-\frac{\sqrt{3}}{2} \sqrt{1-x^{2}}\right)=-2 x \\ ...
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