Evaluate: `tan{2t a n^-1 (1/5)-pi/4}`

Explanation

`2 \tan ^{-1} \frac{1}{5}=\tan ^{-1} \frac{1}{5}+\tan ^{-1} \frac{1}{5}`



`=\tan ^{-1} \frac{\frac{1}{5}+\frac{1}{5}}{1-\frac{1}{5} \cdot \frac{1}{5}}=\tan ^{-1} \frac{\frac{2}{5}}{\frac{24}{25}}=\tan ^{-1} \frac{5}{12} `




`\tan (2 \tan ^{-1} \frac{1}{5}-\frac{\pi}{4})div(tan (\tan ^{-1} \frac{5}{12}-\frac{\pi}{4}))`




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