Solve for `x :` `2tan^(-1)(cosx)=tan^(-1)(2cos e cx)`

Explanation

`\Rightarrow \tan ^{-1}(\frac{2 \cos x}{1-\cos ^{2} x})=\tan ^{-1}(2 \operatorname{cosec} x)[\∵ 2 \tan ^{-1} x=\tan ^{-1}(2 \frac{x}{1-x^{2}})]`



`\Rightarrow\frac{2 \cos x}{\sin ^{2} x}=2 \operatorname{cosec} x`




`\Rightarrow \frac{\cos x}{\sin ^{2} x}=\frac{1}{\sin x}`




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