Solve for `x` : `tan^(-1)((2x)/(1-x^2))+cot^(-1)((1-x^2)/(2x))=pi/3,-1ltxlt1`

Explanation

`\tan ^{-1}(\frac{2 x}{1-x^{2}})+\cot ^{-1}(\frac{1-x^{2}}{2 x})=\frac{\pi}{3}
tan ^{-1}(\frac{2 x}{1-x^{2}})+\tan ^{-1}(\frac{2 x}{1-x^{2}})=\frac{\pi}{3}`


`2 \tan ^{-1}(\frac{2 x}{1-x^{2}})=\frac{\pi}{3}`



` \tan ^{-1}(\frac{2 x}{1-x^{2}})=\frac{\pi}{6}`



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