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Prove the following: 2\ sin^(-1)(3/5)=ta...

Prove the following: `2\ sin^(-1)(3/5)=tan^(-1)(24/7)`

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To prove that \( 2 \sin^{-1}\left(\frac{3}{5}\right) = \tan^{-1}\left(\frac{24}{7}\right) \), we will start by evaluating the left-hand side (LHS) and show that it equals the right-hand side (RHS). ### Step 1: Evaluate the LHS We have: \[ \text{LHS} = 2 \sin^{-1}\left(\frac{3}{5}\right) \] ...
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sin^(-1)(3/5)+tan^(-1)(1/7)=

Prove the following: 4tan^(-1)(1)/(5)-tan^(-1)(1)/(70)+tan^(-1)(1)/(99)=(pi)/(4)2tan^(-1)(1)/(5)+sec^(-1)(5sqrt(2))/(7)+2tan^(-1)(1)/(8)=(pi)/(4)

Knowledge Check

  • sin^(-1)(3/5)+tan^(-1)(1/7)=

    A
    `pi/4`
    B
    `pi/2`
    C
    `cos^(-1)"4/5`
    D
    `pi`
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