Prove the following: `2\ sin^(-1)(3/5)=tan^(-1)(24/7)`

Explanation

To prove that \( 2 \sin^{-1}\left(\frac{3}{5}\right) = \tan^{-1}\left(\frac{24}{7}\right) \), we will start by evaluating the left-hand side (LHS) and show that it equals the right-hand side (RHS).

### Step 1: Evaluate the LHS
We have:
\[ \text{LHS} = 2 \sin^{-1}\left(\frac{3}{5}\right) \]

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