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Write the value of cos(2\ sin^(-1)1/3) ....

Write the value of `cos(2\ sin^(-1)1/3)` .

Text Solution

Verified by Experts

Given,
`cos(2sin^(−1)(1/3)​)`
Let `sin^(−1) (1/3)​=theta`
`=>sintheta=1/3​`
`=>sin^2theta=1/9​`
`cos(2sin^(−1) (1/3​)`
`=cos(2theta)`
`=1−2sin^2theta`
...
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