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If cos((sin^(-1)2)/5+cos^(-1)x)=0 find t...

If `cos((sin^(-1)2)/5+cos^(-1)x)=0` find the value of `xdot`

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`sin^(-1)((2)/5)+cos^(-1)x=cos^(-1)0=frac{pi}{2}`
`sin^(-1)(2/5)+frac{pi}{2}-sin^(-1)x=frac{pi}{2}`
`sin^(-1)x=sin^(-1)(2/5)`
`x=2/5`
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RD SHARMA-INVERSE TRIGONOMETRIC FUNCTION-Solved Examples And Exercises
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  2. Find the value of 2\ sec^(-1)2+sin^(-1)(1/2) .

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