If `alpha=tan^(-1)(t a n(5pi)/4)a n dbeta=tan^(-1)(-tan(2pi)/3),t h e n` `4alpha=3beta` (b) `3alpha=4beta` (c) `alpha-beta=74alpha=(3beta)/(12)` none of these

Explanation

We have given

`alpha=tan^(-1)(t a n(5pi)/4)`

`alpha=tan^(-1)(tan(pi+(pi)/4))`

`alpha=tan^(-1)(tan((pi)/4))`

`alpha=(pi)/4`

`4alpha=pi ...........(1)`

`beta=tan^(-1)(-tan((2pi)/3))`

`beta=tan^(-1)(-tan(pi-(pi)/3))`

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