The value of `sin^(-1)(cos(33pi)/5)` is `(3pi)/5` (b) `-pi/(10)` (c) `pi/(10)` (d) `(7pi)/5`

Explanation

We have to find

`sin^(-1)(cos((33pi)/5))`

`sin^(-1)(cos((33pi)/5))=sin^(-1)(cos((30pi+3pi)/5))`

`=sin^(-1)(cos(6pi+(3pi)/5))`

`sin^(-1)(cos((3pi)/5))`

`=sin^(-1)(sin(((pi)/2)-((3pi))/5))`

`=sin^(-1)(sin((-pi)/10))`

`=-(pi)/10`

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