If `theta=sin^(-1){sin(-600^@)}` , then one of the possible values of `theta` is `pi/3` (b) `pi/2` (c) `(2pi)/3` (d) `(-2pi)/3`

Explanation

We have given

`theta=sin^(-1){sin(-600^o)}`

`theta=sin^(-1){-sin((360^o)+240^o)}`

`theta=sin^(-1){-sin(240^o)}`

`theta=sin^(-1){sin((180^o)+60^o)}`

`theta=sin^(-1){sin(60^o)}`

`theta=(pi)/3`

Hence correct option is (a).