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If [(x-y ,z),(2x-y,omega)]=[(-1 ,4),( 0 ...

If `[(x-y ,z),(2x-y,omega)]=[(-1 ,4),( 0 ,5)]` , find `x ,\ y ,\ z ,\ omega` .

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Equating, we get
`x - y = -1 … (i)`
` 2x - y = 0 …(ii)`
` z = 4, w = 5`
(ii) – (i) `=> 2x – y – x + y = 0 + 1`
` x = 1` and `y = 2`
`x + y = 2 + 1 = 3`.
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