If `A=[alpha0 1 1]` and `B=[1 0 5 1]` , find the values of `alpha` for which `A^2=B` .

If A=[[alpha,01,1]] and B=[[1,05,1]], find the values of alpha for which A^(2),=B

If A=[[alpha,00,1]] and B=[[16,00,1]] then the value of alpha for which A^(2),=B is

If {:A=[(alpha,0),(1,1)]andB=[(1,0),(5,1)]:} , then te value of alpha for which A^2=B , is

If A = [{:(alpha, 0), (1, 1):}] " and " B = [{:(1, 0), (5, 1):}] then value of alpha for which A^(2) = B , is

if A=[[alpha,01,1]],B=[[1,03,1]] and A^(2)=B then find the value of alpha it possible

If A=[(alpha,0),(1,1)] and B=[(9,a),(b,c)] and A^(2)=B , then the value of a + b + c is

If B = [{:(5, 2alpha, 1),(0, 2, 1),(alpha, 3, -1):}] is the inverse of a 3 xx 3 matrix A, then the sum of all values of alpha for which det (A) + 1 =0, is

If alpha and beta are the roots of x^(2)-a(x-1)+b=0 then find the value of 1/(alpha^(2)-a alpha)+1/(beta^(2)-beta)+2/a+b