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If A=[(4,-1,-4 ),(3, 0,-4),( 3,-1,-3)] ,...

If `A=[(4,-1,-4 ),(3, 0,-4),( 3,-1,-3)]` , show that `A^2=I_3`

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Given that,
`A=[(4,-1,-4 ),(3, 0,-4),( 3,-1,-3)]`
`A^2=A*A`
`=[(4,-1,-4 ),(3, 0,-4),( 3,-1,-3)][(4,-1,-4 ),(3, 0,-4),( 3,-1,-3)]`
`=[(16-3-12,-4+0+4,-16+4+12),(12+0-12,-3+0+4,-12+0+12),(12-3-9,-3+0+3,-12+4+9)]`
`=[(1,0,0),(0,1,0),(0,0,1)]`
`=I_3`
`therefore A^2=I_3`
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