If `A=[(3,-5),(-4, 2)]` , find `A^2-5A-14 Idot`

Explanation

To solve the problem, we need to find \( A^2 - 5A - 14I \), where \( A = \begin{pmatrix} 3 & -5 \\ -4 & 2 \end{pmatrix} \) and \( I \) is the identity matrix of order 2, which is \( I = \begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix} \).

### Step 1: Calculate \( A^2 \)

To find \( A^2 \), we multiply matrix \( A \) by itself:

\[
A^2 = A \cdot A = \begin{pmatrix} 3 & -5 \\ -4 & 2 \end{pmatrix} \cdot \begin{pmatrix} 3 & -5 \\ -4 & 2 \end{pmatrix}
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