If `A=[(3,-5),(-4, 2)]` , then find `A^2-5A-14 I` .

Explanation

To solve the problem, we need to find the expression \( A^2 - 5A - 14I \) where \( A = \begin{pmatrix} 3 & -5 \\ -4 & 2 \end{pmatrix} \) and \( I \) is the identity matrix of the same order as \( A \).

### Step 1: Calculate \( A^2 \)

To calculate \( A^2 \), we multiply matrix \( A \) by itself:

\[
A^2 = A \cdot A = \begin{pmatrix} 3 & -5 \\ -4 & 2 \end{pmatrix} \cdot \begin{pmatrix} 3 & -5 \\ -4 & 2 \end{pmatrix}
...